80 г                                         Х г  Ca          +       2HCl     =      CaCl2      +     H2n = 1 моль                          n = 1 мольMr = 40 г/моль                   Mr = 110 г/мольm = 40 г                               m = 110 г80 г Са    -    Х г CaCl240 г Са    -   110 г CaCl2m(CaCl2) = 80 * 110 / 40 = 220 г