Дано:                               Решение:m(Mg)=1,2 г            1,2 г                                                     Х лНайти:                     Mg         +       2HCl   =    MgCl2    +   H2V(H2)=                 n=1 моль                                           n=1 моль                              Mr = 24 г/моль                                Vm=22,4 л/моль                              m=24 г                                             V = 22,4 л1,2 г Mg    -    Х л Н224 г Mg    -    22,4 л Н2V(H2) = 1,2 * 22,4 / 24 = 1,12 л