1. 32⁰²·4⁰⁶=(2⁵)⁰²(·2²)⁰⁶=2¹·2^(1,2)
     16^(0,3)·2^(0,1)=(2⁴)^(0,3)·2^(0,1)=2^(1,2)·2^(0,1)
2¹·2^(1,2)/ 2^(1,2)·2^(0,1)= 2/ 2^(0,1) =2^(1-0,1)=2^( 0,9)/
2.(1-0,5a)²+2a^(0,5)=1- 2a^(0,5)+0,25a²+ 2a^(0,5)=1+0,25a²
3.(y^(1/2)-3)·2 (y^(1/2)+6 (y^(1/2)=2y- 6(y^(1/2)+6 (y^(1/2)=2y