1,15 г                                                             Х л   2Na        +       2H2O     =      2NaOH       +    H2n = 2 моль                                                       n = 1 мольMr = 23 г/моль                                                Vm=22,4 л/мольm = 46 г                                                           V = 22,4 л1,15 г Na   -    Х л Н246 г Na      -     22,4 л Н2V(H2) = 1,15 * 22,4 / 46 = 0,56 л