Pb3o4=pbo*pb2o3PbO+H₂=Pb+H₂OPb₂O₃+3H₂=2Pb+3H₂Oω(PbO)=(207+16)/(207*3+64)=223/685=0.3255m(PbO)=68.5*0.3255=22.3гn(PbO)=22.3/223=0.1 мольm(Pb₁)=0.1*223=22.3 граммаω(Pb₂O₃)=1-0.3255=0.6745m(Pb₂O₃)=68.5*0.6745=46.2гn(Pb₂O₃)=46.2/685=0.067мольn(Pb₂O₃)=0.134мольm(Pb)=30гM(Pb)=30+22.3=52.3г