Yggrius 4 ноября 2019 в 12:40
![\sqrt{} \sqrt{3} \sqrt[3]{9}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%7D%20%5Csqrt%7B3%7D%20%5Csqrt%5B3%5D%7B9%7D%20 "\sqrt{} \sqrt{3} \sqrt[3]{9}")
÷![\sqrt[4]{27}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B27%7D%20 "\sqrt[4]{27}")
плес
÷
плес
=(3^(1/2)*9^(1/6)^(1/2)/27^(1/4)=(3^(1/2)*3^(1/3))^(1/2)/27^(1/4)=
=(3^(5/6))^(1/2)/3^(3/4)=3^(5/12)/3^(3/4)=3^(5/12-3/4)=3^(-1/3)=1/∛3.
∛9=3^(2/3)
√((3^1/2)*3(2/3))=√(3^(1/2+2/3))=√(3^(5/6))=3^(5/6)^(1/2)=3^(5/12)
27^(1/4)=3^(3/4)
3^(5/12)/3^(3/4)=3^(5/12-3/4)=3^(-1/3)=1/∛3.
=(3^(5/6))^(1/2)/3^(3/4)=3^(5/12)/3^(3/4)=3^(5/12-3/4)=3^(-1/3)=1/∛3.
∛9=3^(2/3)
√((3^1/2)*3(2/3))=√(3^(1/2+2/3))=√(3^(5/6))=3^(5/6)^(1/2)=3^(5/12)
27^(1/4)=3^(3/4)
3^(5/12)/3^(3/4)=3^(5/12-3/4)=3^(-1/3)=1/∛3.
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