9,8 г                                         Х г     H2SO4       +       BaCl2     =    BaSO4     +    2HCln = 1 моль                                   n = 1 мольMr = 98 г/моль                           Mr = 233 г/мольm = 98 г                                      m = 233 г9,8 г H2SO4   -   Х г BaSO498 г H2SO4    -    233 г BaSO4m(BaSO4) = 9,8 * 233 / 98 = 23,3 г