9,8 г                                      Х г    H2SO4     +     BaCl2    =     BaSO4      + 2HCl n = 1 моль                             n = 1 мольMr = 98 г/моль                       Mr = 233 г/мольm = 98 г                                  m = 233 г9,8 г H2SO4   -   Х г BaSO498 г H2SO4   -    233 г BaSO4m(BaSO4) = 9,8 * 233 / 98 = 23,3 г